Re: Additions to PHP_Compat

Guys, sorry - but I don't see the problem you all are seeing... ? Once the constant is defined (and it will only be defined once) there is no subsequent call to fopen(). A constant is a constant is a constant :-) Regards, mike Stefan Neufeind wrote: > On 26 May 2004 at 18:47, Lorenzo Alberton wrote: > > >>On Wed, 26 May 2004 18:09:30 +0200, Michael Wallner wrote: >> >>>Hi Stefan Neufeind, you wrote: >>> >>>>>Could these be added to PHP_Compat? >>>>> >>>>>if (!defined('STDIN')) { >>>>>define('STDIN', fopen('php://stdin', 'r')); >>>>>} >>>>>--- >>>>>if (!defined('STDOUT')) { >>>>>define('STDOUT', fopen('php://stdout', 'w')); >>>>>} >>>>>--- >>>>>if (!defined('STDERR')) { >>>>>define('STDERR', fopen('php://stderr', 'w')); >>>>>} >>>> >>>>If you use it in a program that e.g. does multiple writes to >>>>STDOUT, >>>>am I wrong that this would open the file again and again for each >>>>of the output-calls, resulting in many open files and never (until >>>>script end) closing any of these? Or do these calls always return >>>>the same handler to the stdout etc. (not tested)? >>> >>>I hope I got you right: >>>Once STDIN is defined it won't step into the if >>>condition any more, so php://stdin etc. is only >>>opened once. >> >>I think Stefan's worries have some ground... >>each time I *use* the constant STDIN, a fopen call >>will be issued (is it correct?). >>I never tried something like that, but the definition >>above looks more like a C macro than a define... >> >>What about: >>=========== >>if (!defined('STDIN')) { >> $_stdin = fopen('php://stdin', 'r'); >> define('STDIN', &$_stdin); >>} >>=========== >> >>of course it is absolutely untested, but it should >>give an idea of what Stefan was trying to say >>and a possible solution (?). >> >>When I use the STDIN constant, I want THE pointer >>back, not a NEW pointer each time... > > > Just a quick test I tried (php 4.3.4-cli on Linux): > > <? > define('ASTDIN', fopen('php://stdin', 'r')); > define('ASTDOUT', fopen('php://stdout', 'w')); > > var_dump($a = ASTDIN); > var_dump($b = ASTDIN); > var_dump($a === $b); > var_dump($c = ASTDOUT); > ?> > > gives: > > resource(1) of type (stream) > resource(1) of type (stream) > bool(true) > resource(2) of type (stream) > > > So I suppose that PHP doesn't really "open" stdin, but returns the > same stdin-resource again? Would be nice if somebody with a debugger > could check if fopen is called twice ... in this case we could save > some time using Mike's workaround he mentioned above. > > Anyway, I think such functionality for "really old php" is a good > idea. > > Stefan -- Michael - < mike(@)php.net >

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