Re: DataObject insert problem

Ryan King wrote:

Sorry for the slowness.. Here's my media section: [media] id = 129 data = 257

The Generator thinks this is a MySQL TIMESTAMP.. - can you send me the output from SHOW CREATE TABLE media; Regards Alan

created_datetime = 14 short_description = 2 type = 130 file_name = 2 long_description = 2 Thanks, Ryan On Monday, March 08, 2004, at 04:52PM, Norbert Mocsnik <pear-general@mocsnik.hu> wrote:

Hello, Could you send the [media] section from your databasename.ini to the list? Regards, Norbert Ryan King wrote:

$media = DB_DataObject::factory('media'); $media->setId($id); $media->setShort_description($short_description); $media->setLong_description($long_description); if (is_file($_FILES['media']['tmp_name'])) { $media->setType($_FILES['media']['type']); $media->setFile_name($_FILES['media']['name']); $file_path = $_FILES['media']['tmp_name']; $data = file_get_contents($file_path) or die( "Can't open file!" ); $media->setData(base64_encode($data)); } When I then call $media->insert(), the sql that is produced does not include the 'data' field. When I dump the $media object, the encoded file is in the object, but for some reason does not get included in the sql insert statement. I've poked around in the DataObject source, but have not been able to figure out what's going on. -Ryan --------- http://homepage.mac.com/ryansking/

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