Re: HTML_QuickForm instant display of an element
| From: | Antti | Date: | Sun, 16 May 2004 00:13:25 +0000 |
| Subject: | Re: HTML_QuickForm instant display of an element | ||
| References: | 1 2 | Groups: | php.pear.general |
| Request: | Send a blank email to pear-general+get-12473@lists.php.net to get a copy of this message | ||
On Thu, 2004-05-13 at 10:12 +0400, Alexey Borzov wrote:
> Hi!
>
> Antti wrote:
> > What is the correct way to just echo an element independently instead of
> > 'collecting' the elements with addElement() and then echoing them all at
> > once with display()? I need to add a checkbox for every table row so I
> > can't echo the whole form at once 'cause the checkboxes are the same
> > form.
>
>
> $element =& $form->createElement(...);
> $element->display();
>
> you can also directly instantiate element class, without using createElement()
>
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Say I display these elements using createElement(), how do I get the
<form></form> tags surround them?
One other question. What's wrong with this:
$formPl= new
HTML_QuickForm('selectPlaylist',NULL,NULL,"class='table'");
$query = "select id,login,name,public from playlists order by
login";
$test =& $formPl->addElement('select','list','Playlist:');
$test->loadQuery($mysqlConnection,$query,'id','name');
$formPl->display();
I'm not getting any options to the select box.
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