Re: DB_Dataobject and complex joins
| From: | Ian P. Christian | Date: | Wed, 19 May 2004 17:16:41 +0000 |
| Subject: | Re: DB_Dataobject and complex joins | ||
| References: | 1 2 | Groups: | php.pear.general |
| Request: | Send a blank email to pear-general+get-12627@lists.php.net to get a copy of this message | ||
Quoting Alan Knowles <alan@akbkhome.com>:
'should' Do it... I tried this :) Perhaps I should have mentioned that in my first email. The result of that is as follows: SELECT count(radacct.RadAcctId) as DATAOBJECT_NUM FROM radacct LEFT JOIN radcheck ON radcheck.UserName=radacct.UserName WHERE radcheck.Attribute = 'Password' This actually gives different results from this. (which is what I'm after) SELECT * FROM radacct LEFT JOIN radcheck ON radcheck.Username = radacct.Username AND radcheck.Attribute = 'Password' Notice the last of the WHERE clause. Thanks for your help again AK! Kind Regards, Ian$radUser =& DB_DataObject::factory('Radacct'); $radCheck =& DB_DataObject::factory('Radcheck');$radCheck->Attribute = 'Password';$radUser->joinAdd($radCheck, 'LEFT', 'radcheck');