Re: Weird $_GET behaviour with DB_DataObject_FormBuilder

Very strange behavior.... I would try a few more things. $e = (int)$_GET['id']; This is the right way to cast to an int. You could also try: $e = (int)($_GET['id']); $e = intval($_GET['id']); Are you sure you're using $e right? Typed the var right? You could also try: $e = (string)(int)$_GET['id']; Are you sure the right key is being SELECTed? Try doing: DB_DataObject::debugLevel(5); and seeing what the SQL looks like. Try: $do->get('id', $e); On Fri, 09 Jul 2004 16:37:42 -0500, Sarah Gray <sarah@fabled.net> wrote: > Hello Pear List, > > This one is weird. Thanks in advance to anyone with insight / advice. > > Summary: > php 4.3.2 and the formBuilder in Beta (not from CVS), 0.9.0 > When I try to use a value passed in from the $_GET array to plug into > my DataObject ( for editing form objects), > DB_DataObject_FormBuilder does not properly update the object. In all > cases it *does* fill in the form values with the right > values from said object -- it just does not discrimate correctly between > insert and update. > When I use plain ints or other variables that are not from $_GET, the > thing works fine. > > Multiple tests seem to trace to: every time I try using the $_GET array > values (as values or as a conditional), my code does not work as > planned. > > Is there any reason this code block shouldn't work? To create a new > object or edit existing... > > $do = DB_DataObject::factory('mc_Programs'); > if( isset($_GET['id']) ){ > $value = $_GET['id'] + 0; // to cast the value to int > $do->get($value); > } > $fg =& DB_DataObject_FormBuilder::create($do); > > If it shouldn't work -- why not? > If it should work, it doesn't. > I've listed all my code samples / examples below and would love advice. > > Details and extended examples below this line: > > My entire code to create new object. Works. > > $do = DB_DataObject::factory('mc_Programs'); > $fg =& DB_DataObject_FormBuilder::create($do); > $form =& $fg->getForm(); > $form->addElement('image', 'submit', > '/images/submit_CreateNewProgram.gif' ); // IMG submit > if ($form->validate()) { > $form->process(array(&$fg,'processForm'), false); > $form->freeze(); > } > > Now, same code, but to edit existing object // Works. updates object > with pk 3 > > $do = DB_DataObject::factory('mc_Programs'); > $do->get(3); > $fg =& DB_DataObject_FormBuilder::create($do); > $form =& $fg->getForm(); > $form->addElement('image', 'submit', > '/images/submit_CreateNewProgram.gif' ); // IMG submit > if ($form->validate()) { > $form->process(array(&$fg,'processForm'), false); > $form->freeze(); > } > > The following examples are working / not working in a way I don't > understand. > > NOTE: I am only writing the code that is inserted between this line: > $do = DB_DataObject::factory('mc_Programs'); > and this line: > $fg =& DB_DataObject_FormBuilder::create($do); > But I have made no changes to the rest of the code block that I printed > above. > > EXAMPLES > 1. This works: // updates object with pk 3 > $e = 3; > $do->get($e); > > 2. This works // updates object with pk 3 > $e = '3'; // assign string ( to mock how $_GET['id'] comes in as a > string) > $e = $e + 0; // switch to int, just like I did with $_GET['id'] > $do->get($e); > > 3. This DOESN'T Work (results of echo and print_r statements printed > next to if statements so you can see results) > Instead, this creates a new entry. > > if( $_GET['id'] ){ > echo 'in if > <br>'; // in if > echo 'gettype ID=' . gettype( $_GET['id'] ) . '<br>'; > // gettype > ID=string > print_r( $_GET > ); // Array ( [id] > => 0002 ) > $e = $_GET['id'] + 0; > echo '<br>e: ' . $e . '<br>'; > // e: 2 > echo "gettype e=" . gettype($e); // > gettype e=integer > $do->get($e); > echo '<br>leaving > if'; // leaving if > } > > 4. And, if I do this -- leaving the $do->get OUTSIDE of the if > statement, > > if( $_GET['id'] ){ > echo 'in if > <br>'; // in > if > echo 'gettype ID=' . gettype( $_GET['id'] ) . '<br>'; > // > gettype ID=string > print_r( $_GET > ); // Array ( > [id] => 0001 ) > $e = $_GET['id'] + 0; > // e: 1 > echo '<br>e: ' . $e . '<br>'; > echo "gettype e=" . gettype($e); > // gettype e=integer > echo '<br>leaving > if'; //leaving if > } > > $do->get($e); > > I get this error: > DB_DataObject Error: No Value specified for getdb_dataobject_error > Object > ( > [error_message_prefix] => > [mode] => 16 > [level] => 1024 > [code] => -1 > [message] => DB_DataObject Error: No Value specified for get > > 5. This works // updates the object: > > if( 1== 1){ > $e = 4; > } > $do->get($e); > > 6. This does not work: // instead creates new object (but strangely, > does NOT give the error message seen in example #4 about "No Value > specified for getdb_dataobject_error...") even though the get is > similarly outside of the if statement > > if( 1== 1){ > $e = $_GET['id'] + 0; > } > $do->get($e); > > _________________________________ > In summary: > I've tried the above and a few other things. > I am confused. > I would appreciate any insight. > > Thanks, > > s. > > -- > PEAR General Mailing List (http://pear.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > !DSPAM:40ef0e04158051436513693! > > -- DB_DataObject_FormBuilder - The database at your fingertips http://pear.php.net/package/DB_DataObject_FormBuilder paperCrane --Justin Patrin--