Re: quickform post

> > where? > > $form = new HTML_QuickForm('frmTest', 'post','audioin.php'); > > ? > > or > > $s =& $form->createElement('select','lang','Select > > language: '); > > or both? > > Cheers > > Antoine > > ps, I tried all three combos and none worked :-(. > > > > After the form is posted, you should be accessing it as > $_POST['lang'], not $_Post['lang'] as you had. right... sorry, I wrote and didn't copy and paste, and... I am not that good with forms... it was $_POST['lang'] in the receiving form. I, very stupidly (I really am not as stupid as it would seem, I hope!!!), didn't check the source being created and didn't notice that my query was not setting a value for the select entries. So that was the problem. I still haven't worked out how to use loadQuery to do what I want with a single column result, but with loadDBResult and repeating that column I am now able to get values across to the other php script (via post). I simply was sending an empty string, hence the lack of action. Cheers Antoine ps. If anyone has any suggestions for how to put a values column into loadQuery (for single column results) it would be nice to know... save me a line of code that way! -- G System, The Evolving GUniverse - http://www.g-system.at