Re: Problems whith Structures_DataGrid 0.6.0

On Fri, 24 Dec 2004 02:21:27 +0100, Bernardo Cabezas Serra <bercab@bergantells.net> wrote: > Hi all, > > I have been using Structures_DataGrid for some projects, with the old > version, with DataObjects datasources, using my own bind() method. > > New version's approach of drivers for datasources seems cool, so i tried to migrate > projects to 0.6.0. > > The problem is that i haven't been able to get it running, even with the > basic examples which comes whith the package. I always get an empty > table rendered. > > When, as an example, i create a datagrid $ds and bind with the basic > array $rs which comes whith the example, this whorks: > > echo $dg->_dataSource->dump(); > > It dumps the table, but > > $dg->render(); > > does not work. When trying to guess what's going on, i've seen that the > problem seems that fetchDataSource() method called from getTable() > (inside the HTML_Table renderer) finds an empty "_datasource" property. > > I mean: > > $dg->_datasource > > contains a valid structures_datagrid_datasource_array > Object, but > > $dg->renderer->_dg->_datasource > > is null, and also from inside the renderer, (the property > _dg->_datasource is null), thus when _$dg->fetchDataSource() is > called from inside the renderer (as a result of $dg->render() ) > returns no valid recordSet or columnSet. > > if called from the main test program, $dg->fetchDataSource returns recordset > and columnSet correctly. > > Is this normal and i'm doing any other thing wrong, or there could be a > problem whith the renderer's "_dg" reference? > > I just now have find that doing: > > $dg = new Structures_DataGrid(20); Try $dg =& new Structures_DataGrid(); > $dg->renderer->_dg = &$dg; > > it seems to work correctly, but does not work without the second > line... > why could it be? > > Thank you very much, and sorry for my bad "spanglish" ;-) > > PS: I'm using php 4.3.9, after downgrading from 4.3.10 due to the overload() > bug. > -- Justin Patrin