Re: Two questiens regarding Structures_DataGrid

On 7/19/05, Pupeno <pupeno@pupeno.com> wrote: > Hello, > tryng to use DataGrid I have found some problems, by now I have two questions. > - How do I specify a relationship, that is, one of thi fields being listed is > an id that should be used to gather info from another table, this > relationship is specified an tho tables (MySQL InnoDB) and I am using > DB_DataObject, basically doing: You can do 2 things here. One is to use a column formatter. You can have yoru formatter get the linked object and return what you want to display. or You can set fb_linkDisplayFields in your linked dataobject and turn on formbuilder_integration for the DataObject DataSource. > $plan = DB_DataObject::factory('Plans'); > require_once('Structures/DataGrid.php'); > $plansTable =& new Structures_DataGrid(10); > $plansTable->bind($plan); > - The other is what is going on tha after defining this column: > $plansTable->addColumn(new Structures_DataGrid_Column('Commands', null, > null, > array('class' => 'commands'), null, 'commands()')); > which call back to: > function commands($params){ > return 'a'; > } > I get this notices > Notice: Undefined variable: in /usr/lib/php/Structures/DataGrid/Column.php on > line 183 [1] > > > [1] Now that I think about it, maybe Structures_DataGrid is not ready to run > on E_ALL reporting ? > All PEAR packages should work with E_ALL. Please report this as a bug. -- Justin Patrin