Re: Smarty With Pear Datagrid

Hi Moses, First, which version of Structures_DataGrid are you using ? Please use the CVS version if possible, not 0.6.3. moses@softwaysolutions.com wrote:

    I am using YDFramework in my applications which uses Smarty as its Template Engine.

            $datagrid =& new Structures_DataGrid   (10,null ,DATAGRID_RENDER_SMARTY);          

which gives the following error

         Failed opening required 'Smarty/Smarty.class.php' 

Now I downloaded Smarty and place it in my application folder. again I get the Following Error Fatal error: Cannot redeclare class smarty in D:\web\Moses\test\pear\DataGrid\Smarty\Smarty.class.php on line 65

    Since  YDFramework is coupled with smarty it already initialize the Class Smarty  so the class can be redeclared.

    Now what to do. 

The recommended way of using the Smarty renderer is this (You need the CVS version for this to work) : $datagrid =& new Structures_DataGrid(10); $datagrid->fill($smarty); where $smarty is a Smarty instance. The best, in you case, I suppose, would be to get the smarty instance that's internally used by the YDFramework. Reading : http://ydframework.berlios.de/doc/ydtemplate_syntax.html it looks like YDTemplate is a descendant of Smarty, or implements the same interface. So you might : $template = new YDTemplate(); $datagrid->fill($template); Note : fill() might not detect that $template is a $smarty compatible object. In this case you will need to set the type : $datagrid->fill($template, array(), DATAGRID_RENDER_SMARTY); After calling fill(), new variables and functions will be available in your templates. Please the "GENERAL NOTES" section at the top of DataGrid/Renderer/Smarty.php for detailed informations about this.

Again       
     I tried with working with creating the instance of datagrid without passing the parameter DATAGRID_RENDER_SMARTY                     $datagrid =& new Structures_DataGrid (10);
       Now I dont get any error and I am passing the Datagrid object to the smarty template and its working Fine.

I don't really understand what you mean by "passing the Datagrid object to the smarty template".

I want to clarify some doubts...

          1) Is there any particular reason or use  to Pass the argument   DATAGRID_RENDER_SMARTY while using Smarty.

Normally you don't need to use the DATAGRID_RENDER_SMARTY constant. fill() is able to auto-detect the type of the container that you pass to it. But if you use a "smarty compatible" object, as YDTemplate might be, then you need to specify the type as shown above.

          2) Though I am not using the argument its is working.  Why!!!!

Because you are using DATAGRID_RENDER_HTMLTABLE which is the default renderer used by the datagrid. It generates HTML, and I suppose you manage to paste it into your Smarty templates. But, for sure, that's a bad practice because you handle presentation through external code, when you're supposed to do that using Smarty templates, Smarty variables, etc.... Please take a look at the GENERAL NOTES section of DataGrid/Renderer/Smarty.php, from the CVS version. Smarty support in Structures_DataGrid has been much improved. Regards, -- og