Re: QuickForm this.form.submit(), errors don't show up

Hi, Mark Steudel wrote:

Actually I meant the server side message, not the javascript error message.

Use the $trackSubmit parameter of QuickForm's constructor: http://pear.php.net/manual/en/package.html.html-quickform.html-quickform.html-quickform.php Clarification: if you submit your form currently the $_POST array may be completely empty and form will be considered not submitted. Non-selected checkboxes do not appear in $_POST and since you are using form.submit() the name=value of your submit button isn't sent, either. The other possible approach is changing your javascript to this.value='Submitting form please wait...';this.disabled=true;return true;

Example form $form =& new HTML_QuickForm('testform'); // Creates a checkboxes group using an array of separators $checkbox[] = &HTML_QuickForm::createElement('checkbox', 'A', null,

'A');

$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'B', null,

'B');

$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'C', null,

'C');

$checkbox[] = &HTML_QuickForm::createElement('checkbox', 'D', null,

'D');

$form->addGroup($checkbox, 'ichkABC', 'ABCD:', array('&nbsp;', '<br

/>'));

// At least one element is required $form->addGroupRule('ichkABC', 'Please check at least two boxes', 'required', null, 2); $form->addElement( 'submit', 'submitForm', 'Submit Form', array(

"onclick"=>

"this.value='Submitting form please wait...';this.disabled=true;this.form.submit();") );