Re: DataObjects

Barry Steele wrote:

hi, hi

Does anyone have some examples of extending the Validation part of a DataObject? I'm a little slow and the stuff in the manual is not shining a great light on my issue. Essentially it's this:- I have an Actvity (in my case an audit of beach safety) which is linked to a beach and is a long transaction (that is it can take weeks). what I want to do is ensure that when a new audit is entered it cant include a beach that is already subject to an open audit. I've built an insert form that makes this easy but it is still possible for a user to create a new audit by using the back arrow and resubmitting the existing data. Well, i think the better way to avoid duplicate inserts would be delegating this job to your backend RDBMS, adding a unique key ,

then on duplicate insert, the method would return a false because of an already existing tuple. You could too replace the insert() method by your own , which would include an integrity check, a thing like : function insert() {

    $check = new object();
    $check->whereAdd('name = '.$this->name);
    $check->whereAdd('2ndkey = '.$this->2ndkey);
    if ($check->find() > 0) {
             return false;

}

    return parent::insert();

} Or using the same kind of things but out of the insert method(); a thing like: function isInDb() {

    $check = new object();
    $check->whereAdd('name = '.$this->name);
    $check->whereAdd('2ndkey = '.$this->2ndkey);
    if ($check->find() > 0) {
             return true;

} return false; } And then calling this method before insert(); $myobj = new object; $myobj->setFrom($_POST); if (!$myobj->isInDb()) {

    $myobj->insert();

} But maybe, there is a better way to do that ? Alan ?

how do I reference Dept details within the Employee object after a get_link() ? for example emp = new DataObject_Employee; emp->get(123); emp->get_links(); print ($emp->dept->deptName); ??? - I tried thi sonce and failed and could figure it out The way to use links , assuming you've correctly feed the links.ini file, is:

$emp = new DataObject_Employee; $emp->get(123); $dept = $emp->get_link('dept'); print ($dept->deptName); ?? OR using getlinks: $emp = new DataObject_Employee; $emp->get(123); $emp->get_links(); print ($emp->_dept->deptName);

           ^^^^

Thanks Barry

Regards -- Xavier