Re: DataObjects and SQL functions

Michael wrote:

Hi, I want to use the ->insert function of the DataObjects class, but one of the fields in my object is an password field, which has to be converted with the password() function of mysql. Is that possible with DataObjects ?? Yes you can add a method to your class:

function setMyPasswordField($string) { $this->myPasswordField = md5($string); } or something similar. If you want to use the mysql function it a little more complicated I think but not impossible I think HTH jeroen