Re: How do I force to pass an argument by reference?

Hi, On Fri, 2016-02-12 at 16:34 +0600, Ruslan Osmanov wrote: > Please help me to understand what's wrong with my code, or how do I > force passing by reference? From what I can tell the code seems to be correct. The flag is rightly set. The only thing which comes to mind is that the error you're citing is produced by the compiler, not during execution. So maybe there's some magic in the compiler involved. Anyways: I wonder why that is needed. You are passing an object, and an object is passed by handle, so you can manipulate the same object if if passed by value. Taking a reference means that the user eventually can replace the object and references are bad. <?php class C { private $o; public function __construct(stdclass &$o) { $this->o = &$o; } public function getO() { return $this->o; } } $o = new stdclass(); $c = new C($o); $o = 42; var_dump($c->getO()); ? int(42) // no object anymore! Also, at least in PHP 5, you usually get a notable performance penalty as copy-on-write will prevent copies while references disable copy-on-write. I haven't benchmarked this in PHP 7. johannes

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