Help with resources management

Hi there, A while ago, I asked for some links on how to manage resources when creating an extension from an existing C library. I got answers from some of, who I thank a lot [1]. To remind you of my problem, I would like to write an extension that uses functions returning funny types like, for example: SSH_OPTIONS *options_new(); Where SSH_OPTIONS is a structure declared in my ssh library. I have come to this, which seems a lot nicer than before and even compiles, but doesn't return anything other than NULL: ZEND_FUNCTION(ssh_options_new) { zval *options; if (ZEND_NUM_ARGS() != 0) { WRONG_PARAM_COUNT; } options = (zval *) options_new(); ZEND_REGISTER_RESOURCE(return_value, &options, le_ssh); } Now I just had time now to try this again and I am having problem understanding the answers I received back then, mostly because I am not C proficient anymore. For example, Andrey Hristov wrote: " More or less, malloc a variable (in the function you have declared a pointer), register the variable and you get zval. Return this zval to the user. When the user passes back the zval you can check whether it is a resource (IS_RESOURCE or with zend_parse_parameters()) and with the resource you can get back a pointer to the memory previously allocated. Another detail is that you have to provide a pointer to a function which is used by ZE for automatic deallocation (destruction) of the resource, whenever that is needed. This function is usually short and is more or less a cast and efree(). " So applying this answer, how should I cope with this? I'm thinking about something like: ZEND_FUNCTION(ssh_options_new) { if (ZEND_NUM_ARGS() != 0) { WRONG_PARAM_COUNT; } options = malloc(options_new(),sizeof(???)); ZEND_REGISTER_RESOURCE(return_value, &options, le_ssh); } But honestly I really doubt it could be correct. Could somebody give me a hint about this? Thanks in advance, Yannick Warnier [1] I also tried to send the ssh library to someone that asked me (don't remember who) but was blocked by some kind of mail scanner. I can try again if the person asks.