Bug #67781 [Opn]: Use array() instead of square brackets
| From: | ajf@php.net | Date: | Wed, 06 Aug 2014 21:58:17 +0000 |
| Subject: | Bug #67781 [Opn]: Use array() instead of square brackets | ||
| References: | 1 | Groups: | php.standards |
| Request: | Send a blank email to standards-+get-364@lists.php.net to get a copy of this message | ||
Edit report at https://bugs.php.net/bug.php?id=67781&edit=1
ID: 67781
Updated by: ajf@php.net
Reported by: joelm@php.net
Summary: Use array() instead of square brackets
Status: Open
Type: Bug
Package: PHP Language Specification
PHP Version: Irrelevant
Block user comment: N
Private report: N
New Comment:
I'd say "the array literal syntax". It's a literal, not an operator.
Previous Comments:
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[2014-08-06 21:56:18] fa@php.net
I am not a native speaker, but wouldn't "the xy operator" imply some sort of
uniqueness in a general sense?
Especially as "the array operator []" is also "the subscript operator []".
I am thinking along the lines of "when using [] as the(an?) array operator". But that
sounds less succinct and somehow less precise.
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[2014-08-05 17:10:39] joelm@php.net
There was disagreement here:
"Both notations are permitted, and unless weâre going to deprecate one of them, we should
be able to use both. If that causes a significant problem, then IMHO the wrong spelling was chosen
for the new/alternate notation."
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[2014-08-05 17:09:56] joelm@php.net
Description:
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https://github.com/php/php-langspec/blob/master/spec/10-expressions.md#array-creation-operator
It might be better to say that "array(..)" is the 'array creation operator' and
mostly use "array(..)" instead of "[..]" in examples. Most existing PHP code
uses "array(..)" way more than "[..]" (because "[..]" was added very
recently), and I think using "array(..)" as the 'array creation operator' helps
disambiguate it from the subscript operator ("[]").
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Edit this bug report at https://bugs.php.net/bug.php?id=67781&edit=1