Re: [PHP4BETA] Using $GLOBALS array in an object

Is the constructor behavior different also? Meaning if I add a constructor to all my classes, will I also need to modify all my current code thats like this: $var = new Object; to $var = new Object(); Or is it implied? Thanks for the fast answer Zeev. Salty`` ----- Original Message ----- From: "Zeev Suraski" <zeev@zend.com> To: "Bob Silva" <bsilva@umesd.k12.or.us> Cc: <php4beta@lists.php.net> Sent: Friday, April 21, 2000 2:11 AM Subject: Re: [PHP4BETA] Using $GLOBALS array in an object > On Fri, 21 Apr 2000, Bob Silva wrote: > > > In one master include file at the top outside any objects I have: > > > > $CACHE_ROOT = "/cache"; > > > > then inside an object later in the same page I have: > > > > Line 370: var $CACHE_DIR = $GLOBALS["CACHE_ROOT"]; > > > > This is giving a parse error: > > Parse error: parse error in libBravenet.php on line 370 > > > > I have a very similar line where I am setting a class var to a GLOBALS > > variable and it dies there as well. > > This code has worked fine in PHP3 for ages, so I cant figure out whats going > > on. > > > > I do have the optimizer installed, but even disabling that didnt help. > > Any ideas? > > The optimizer doesn't affect the parsing engine, or the behavior of PHP in > general, except for making it run faster. > > As of PHP 4.0, initialization values (for static members, class members or > default function arguments) have to be static (i.e. numbers, static > strings or static array()'s). In order to initialize your cache dir, you > must move the initialization to the class's constructor. > > Zeev > > -- > Zeev Suraski <zeev@zend.com> > http://www.zend.com/ > >