array_splice() RFD

Have a bit of a conceptual problem with array_splice here, and wanted to get feedback from y'all. Right now the way array_splice works is like this: $input = array(1, 2, 3, 4); $removed = array_splice($input, 1, 2, "a", "b"); This would result in $input being array(1, "a", "b", 4). So it basically takes a variable number of arguments and replaces the removed values with them. Now, what if instead of calling a function and passing each new element to it as a parameter you wanted to pass an array of these elements since you don't know how many you will have at run time. Something like: $input = array(1, 2, 3, 4); $repl = array("d", "e", "f"); $removed = array_splice($input, 1, 2, $repl); And $input would be array(1, "d", "e", "f", 4). Which way is more convenient? I'd vote for the second one since it gives you more flexibility. It's just that if you wanted to replace the removed values with an actual array you'd need to do array_splice($input, 1, 2, array($repl)). I'd like to hear your thoughts on this one, -Andrey * Black holes are where God divided by zero. *