Re: modular php build on unix

On Wed, 1 Sep 1999, Gergely Madarasz wrote: > Hello, > > I checked php4 to build a debian package from it and I have concerns > regarding the shared extension build of the packages... > I see the xml module can be build as a shared extension, but the build > script builds a libphpext_xml.so.0.0.0 with a soname libphpext_xml.so.0, > while, I guess, the name of the module should be xml.so and there is no > need for a soname. This is not a library, to be linked against, just a > module to be loaded. The flag -avoid-version to libtool will disable the > version extension in the file generated, but the soname will remain. I > guess that won't be such a big problem. Ok, here is a Makefile.am which almost seems to be working for the shared case... (there is a problem with some 'ln -s' at the end of the compile) Now the problem remains that libtool builds the shared library even if the module is statically built into php3 :) # $Id: Makefile.am,v 1.3 1999/07/24 00:56:56 sas Exp $ phplibdir=$(libdir)/php SRC=xml.c INCLUDES=@INCLUDES@ -I@top_srcdir@ -I@top_srcdir@/libzend noinst_LIBRARIES=libphpext_xml.a libphpext_xml_a_SOURCES=$(SRC) phplib_LTLIBRARIES=xml.la xml_la_SOURCES=$(SRC) xml_la_LIBADD=@XML_LIBS@ xml_la_LDFLAGS=-avoid-version -module EXTRA_LIBS= Greg