SV: SV: [PHP4BETA] unset() bug or feature?

> > Yes. But look at this: > > > > $array[0] = "Set"; > > print count($array); // prints: 1 > > unset ($array[0]); // $array > now contains 0 items. > > reset($array); // This doesn't help > > It doesn't help what? As far as I understand it doesn't reset the internal array pointer to $array[0]. If it would, the subsequent addition to $array[] would be placed in $array[0] and not $array[1] as is the case. > > print count($array); // prints: 0 > > $array[] = "Set"; // Add to > $array (which contains _zero_ items!) > > print count($array); // prints: 1 > > print "$array[0]"; // prints: (nothing) > > print "$array[1]"; // prints: Set > > > > Questions: > > 1. Why isn't the internal array pointer reset when any or > all items are > > unset()? > > Why should it? It should only move if the element being unset is the one > currently pointed by the internal pointer, and then too it shouldn't > reset, but move to the next element. Ok, I won't argue more on that. > > 2. Why doesn't reset() reset the internal array pointer? > > It does. What makes you think it doesn't? See comment above. $array[] = "Set" adds to $array[1] even though $array was just reset(). Shouldn't it add to $array[0] ?? /Johan Ekenberg