Re: Why parse error?
| From: | Nicole Amashta | Date: | Mon, 04 Feb 2002 18:40:51 +0000 |
| Subject: | Re: Why parse error? | ||
| References: | 1 2 | Groups: | php.windows |
| Request: | Send a blank email to php-windows+get-11838@lists.php.net to get a copy of this message | ||
Pardon my error ... I didn't mean that you use & for arrays ... doeth! But
it reminded me of Perl, nonetheless. @ for arrays, % for hashes, & to call
functions ... anyway .... moving along.
Switch out the & for $ and should be fine.
=]
nicole 'doeth!' amashta
www.aeontrek.com
"Nicole Amashta" <430ntr3k@bellsouth.net> wrote in message
news:20020204183502.5942.qmail@pb1.pair.com...
> You have to remember this is PHP and not Perl. You do not need to use the
> ampersand in front of arrays. You always use the $ for variables,
including
> arrays and hashes.
>
> Replace that & with a $, and you should be fine.
>
> Good luck ! :)
>
> Nicole Amashta
> www.aeontrek.com
>
>
> "Andrew Ziem" <andyziem@acmemail.net> wrote in message
> news:3C5AF322.19C5B406@acmemail.net...
> > Hi,
> >
> > I am trying to retreive stored data, and I can't figure out why I
> > receive this PHP error--even after reading PHP documentation and looking
> > at examples--
> >
> > "Parse error: parse error in c:\vol\php\e.php on line 10"
> >
> > The following is my simplified code:
> >
> > <?php
> >
> > mysql_connect("localhost", "root");
> >
> > mysql_select_db("volunteers");
> >
> > $result = mysql_query("SELECT * FROM names WHERE id=$id");
> >
> > &line = mysql_fetch_row(&result);
> >
> > $first = $line["first"];
> > $middle = $line["middle"];
> > $last = $line["last"];
> >
> > $street = $line["street"];
> > $city = $line["city"];
> > $zip = $line["zip"];
> >
> > ?>
> >
> >
> >
> > --
> > Andy Ziem
> > Is Jesus Your Answer?
> > http://www.ChristianAnswers.net/gospel
> >
> >
> >
> >
> >
>
>