RE: [PHP-WIN] PHP_SELF

i think u need to do this: a) convert the mysql result to an array using some iteration function like array_walk(). b) if u r using sessions, save the array as a session variable for subsequent usage. OR if u need to pass it as hidden field, then u should use the serialize() function to pass the value to the form and later use the unserialize() function to get back the original array. //sample $result = mysql_query($qu2); $num = mysql_num_rows($result); //suppose u convert the $result to array $rows then <INPUT TYPE='hidden' VALUE=serialize($rows) NAME='result'> //and after posting the form use $rows = unserialize($_POST['result']) cheers! -----Original Message----- From: Blue Presley [mailto:blue928@carolina.rr.com] Sent: Monday, October 14, 2002 03:12 To: php-windows@lists.php.net Subject: Re: [PHP-WIN] PHP_SELF your error is not with PHP_SELF, it's in your mysql query.. you don't put a semicolon at the end of your statement.. $qu2 ="SELECT * FROM test_tabel ;"; should be $qu2 = "select * from test_table"; anytime you receive the error you got, it's most likely due to a problem with your Query. blue At 08:17 AM 10/13/2002 +0100, you wrote: >hi rodrigo > >i tried this a few months bak but it didn work wirh >forms i alwayz got silly errors which i KNEW ver rong > >anyway i used $PHP_SELF with links > >what u can do is u can make a submit LINK n make it >look like a button (if u preffer buttons :S) and pass >ur variables thru > >but then there cud be security risks :S > >well i hope dis helps > >luck > >toby .... > > --- Rodrigo San Martin <rodrigo@stud.ntnu.no> wrote: > > Hi > > > > Have a problem. Need to pass a multiple array > > through a form using a > > PHP_SELF. > > I pass it whith a hidden variabel but i get an error > > warning. > > > > "Warning: Supplied argument is not a valid MySQL > > result resource in..." > > > > The code is: > > > > ; > > $result = mysql_query($qu2); > > $num = mysql_num_rows($result); > > > > i take out some info from test_table (there are some > > questions in the table > > that the user need to answer), the user does some > > operation, clicks submit > > and is supposed to be presented whith the next > > question in the table. I pass > > the variable like this: > > > > <INPUT TYPE='hidden' VALUE='$result' NAME='result'> > > > > But no way josey. I get that warning. > > > > Anybody got i nice solution please. > > > > > > > > > > > > ------------------------------------------ > > Rodrigo San Martin > > Institutt for datateknologi og informatikk > > > > http://www.idi.ntnu.no/~rodrigo > > > > > > > > > > -- > > PHP Windows Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > >__________________________________________________ >Do You Yahoo!? >Everything you'll ever need on one web page >from News and Sport to Email and Music Charts >http://uk.my.yahoo.com > >-- >PHP Windows Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php