RE: [PHP-WIN] HELP - problems with mysql and select .

I'm not sure what you are talking about here so I will have to guess... If by JAVA you mean javascript, well that operates client side and it cannot directly interact with a server side PHP script which has finished execution by the time the page is displayed. If you are trying to display data when the user clicks on a form object then I would look into using DHTML or CSS to unhide a previously populated but hidden div/layer. Alternatively javascript can open another window, or have the form re-submit with different parameters - naturally the latter 2 will involve another round trip to the server.... HTH Rich -----Original Message----- From: A. Mikkelsen [mailto:a__mikkelsen@hotmail.com] Sent: 12 November 2002 12:41 To: php-windows@lists.php.net Subject: [PHP-WIN] HELP - problems with mysql and select . Hey. I'm trying to make a page with a dropdown (data from MYSQL) where I with a click on the choosen line get the information an the user in a table beneth. The dropdown box works, but the click part and the java part doesn't... Can anyone help ???? JAVA Function : function show() { show_list = 1; } CODE : <TR> <TD COLSPAN="2"> <FORM METHOD = "post" NAME="update_user" ACTION = "<? echo $PHP_SELF ?>"> <INPUT TYPE="Hidden" NAME="action" VALUE="show_users"> <SELECT NAME="wm_id" SIZE="6" STYLE="width=205px"> <?php $show_list = 0; $user_list = generate_user_id_list(); For ($i=0; $i < sizeof($user_list); $i++) { echo "<OPTION VALUE=".$user_list[$i]['wm_id']." onClick=show()>".$user_list[$i]['wm_id']." - ".$user_list[$i]['f_name']." ".$user_list[$i]['l_name']."</OPTION>"; } ?> </TD> </TR> <TR> <TD> <br> <br> <br> <INPUT TYPE="Submit" VALUE="View user" SIZE="10" onClick="show()"> </TD> </TR> <TR> <TD> <?php IF (!$show_list == 0) { echo "<br><br><br><br>TEST"; } ?> </TD> </TR> //A. Mikkelsen -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php