RE: [PHP-WIN] Newbie attempting file open...

You may want to try something like this: $fp = @fopen(<filename>,"r"); if ($fp) { print"An old file was opened!"; } else { $fp = @fopen(<filename>,"w"); fclose($fp); $fp = @fopen(<filename>,"r"); print"New file was created!"; } -----Original Message----- From: William Fisher To: php-windows@lists.php.net Sent: 2003-03-10 19:54 Subject: [PHP-WIN] Newbie attempting file open... The Question: It is my understanding that fopen() using the "r" option will either open the indicated file for read only OR create one if it doesn't exist. fopen() is giving me this error when trying to create/open a file. Warning: fopen(c:/program files/apache group/apache/htdocs/test.txt) [function.fopen]: failed to create stream: No such file or directory in c:\program files\apache group\apache\htdocs\file_open.php on line 5 The Code: What I've written...well...copied... is this: <?php $DOCUMENT_ROOT = $HTTP_SERVER_VARS['DOCUMENT_ROOT']; $fp = fopen("$DOCUMENT_ROOT/test.txt" , "r"); ?> The Guts: Windows ME, Apache 1.3.27, PHP 4.3.1. Why am I using ME? Call it compulsary. I buy the cheap gas, too. Any ideas as to why this is happening? What's this whole file streaming issue? Blessings, Zach Fisher.... --------------------------------- Do you Yahoo!? Yahoo! Tax Center - forms, calculators, tips, and more