DateDiff replacement in PHP

I found this in php.faqts.com, and seems very useful. Jun 16th, 2000 10:08 Robert Brown, Marco Steinacher http://www.php.net/manual/html/function.mktime.html You can do this with the following statement: $diff=abs(mktime(0,0,0,$month1,$day1,$year1)-mktime(0,0,0,$month2,$day2, $year2))/(86400); Explication: ************ mktime() returns seconds since 1.1.1970 for the specified date. Thus the difference mktime([date1])-mktime([date2]) tells us the seconds between [date1] and [date2]. If we divide the absolute value of this difference by the number of seconds per day (24*60*60=86400) we get the number of days between [date1] and [date2]. Example: ******** We want to know the difference between 31.12.1999 and 01.03.2000. The following code tells us the answer: <? $diff=abs(mktime(0,0,0,12,31,1999)-mktime(0,0,0,3,1,2000))/(86400); echo $diff; ?> The script-output is: 61 That is correct then: 1 day (31.12.99) +31 days (in Jan.00) +29 days (in Feb.00) --------- =61 days =========