RE: [PHP-WIN] Re: Regular Expression Question

Okay, thanks for pointing that out. How do we place multiple Replacements in the $replacement argument to preg_replace? I've added a double capture on my regular expression. If it is matched then I replace the the matched pattern by prefix a single character the the value of ${1} from the captured pattern. I have found out that I may need a second expression to capture all of the items in the file <snip> $aStr = array(); $aPat = array(); $aSum = array(); $aStr[] = "1. This is my first Qna"; $aStr[] = " 1. This is my first Qna"; $aStr[] = "11. This is my first Qna"; $aPat[] = "/(^\d{1,2}\.)|(^\s\d{1,2}\.)/"; $aPat[] = "/(^\d{1,2}\.)|(^\s\d{1,2}\.)/"; $aPat[] = "/(^\d{1,2}\.)|(^\s\d{1,2}\.)/"; ****problem is here $rep = "Q\${1}, ${2}"; $aSum = preg_replace($aPat, $rep, $aStr); echo "<P>"; foreach( $aSum as $s ) { echo "string = $s <BR>"; } -- Gerardo S. Rojas mailto: grojas@strategicinc.com -----Original Message----- From: Andrei BEJENARU [mailto:abejenaru@interakt.ro] Sent: Friday, November 21, 2003 9:50 AM To: php-windows@lists.php.net Subject: [PHP-WIN] Re: Regular Expression Question Enclose a capturing group (\d) and the use prefix\${1} inside the replacement. Check out the PHP manual: $string = "April 15, 2003"; $pattern = "/(\w+) (\d+), (\d+)/i"; $replacement = "\${1}1,\$3"; "Gerardo Rojas" <grojas@strategicinc.com> wrote in message news:F0EDCD6B96C14741A2F6B0BE6EB7D9CF6D703B@scsprdm.strategicinc.com... I have a regular expression, that finds what i want. The problem lies in that I don't want to replace this pattern with another. I want to prefix the pattern with a character. Any suggestions as to how I might accomplish this? regular expression = '/^\d\{1,2}\./' -- Gerardo S. Rojas mailto: grojas@strategicinc.com -- PHP Windows Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php