Re: open directory and read the file

I think you have the problem in: $handle_file = fopen ($find_file, "r"); while (!feof ($handle_file)){ $buffer = fgets($handle_file, 4096); echo "$buffer<br>"; } Right? Well, I think the next code could help you: <? $cats = file("test.txt"); for($i=0; $i<count($cats); $i++) { echo $cats[$i]."<br>"; } ?> This prints each line of the text file. I hope it helps you. "Idur" <bakpia_lumpia@yahoo.com> escribió en el mensaje news:20031223174226.80460.qmail@web40507.mail.yahoo.com... > Hi there, > > I want read a directory and open a file inside the directory, for example directory data contains of file: > Computername.txt > IPaddress.txt > status.txt > > and i want search a file on the directory and open it, for example i want search file IPaddress.txt and when file IPaddress.txt found, i want open it, read and display the contains of the file. > > the script that i have is like this : > <?php > $find_file="name.txt"; > if ($handle = opendir('C:\apache\htdocs')){ > while (false !== ($file = readdir($handle))){ > if ($file == $find_file){ > echo " file found $file<br>"; > > // i want to open the file, but i am confuse with the file handle > $handle_file = fopen ($find_file, "r"); > while (!feof ($handle_file)){ > $buffer = fgets($handle_file, 4096); > echo "$buffer<br>"; > } > } > } > closedir($handle); > } > ?> > this script does'nt run correctly i have an error message, "Warning: Supplied argument is not a valid File-Handle resource in c:\apache\htdocs\fseek\readdir.php on line 11" > > I confuse with the file handle, because is different with opening file like usually, what should i do...??? does any one can help me...?? > > Thanx > idur > > > > --------------------------------- > Do you Yahoo!? > Yahoo! Photos - Get your photo on the big screen in Times Square