Re: form to php

You haven't closed your form tag which is causing it to all go wrong. Here is some working code for you: <form action="action.php" method="post"> <p>Your name: <input type="text" name="name"></p> <p>Your age: <input type="text" name="age"></p> <p><input type="submit" /></p> </form> action.php: <?php //Check to see if user has clicked submit if (isset($_POST['name']) && isset($_POST['age'])) { //Check to see if user has entered data in both fields if (!empty($_POST['name']) && !empty($_POST['age'])) { //User has entered data in both fields so display result ?> Hi <?php echo $_POST['name']; ?> .You are <?php echo $_POST['age']; } else { //User has not populated both fields so send a warning to user telling them what to do ?> <script language="javascript" type="text/javascript"> window.alert('You must complete both fields'); </script> <?php } } ?> You would probably find it easier to read if you format your HTML a little, a little formatting goes a long way when it comes to debugging HTML, especially if your using the devils own tables :P "Php mysql" <dailymails4me@yahoo.co.in> wrote in message news:20040729082358.48834.qmail@web8306.mail.in.yahoo.com: > hi list, > > i have managed to successfully install php and i am now going through > the manual and trying a few of the examples given there. The examples i have > tried till now are all working except for one. The example about inputting > in the form and then displaying it through php is not working for me. But > when i run it i get the entire code in action.php instead. > The example i am referring to is: > > form action="action.php" method="post"> <p>Your name: <input > type="text" > name="name" /></p> <p>Your age: <input type="text" > name="age" /></p> > <p><input type="submit" /></p></form > > action.php: > > Hi <?php echo $_POST['name']; ?>.You are <?php echo $_POST['age']; > ?> > > > > Please tell me whts wrong.... > > thanks in advance > > penjo > > Yahoo! India Matrimony: Find your life partneronline.