Re: help in understanding string / integer concatenation

Raymond This produces what I think you want: $str = 'hello' . ($i+1); Mike ----- Original Message ----- From: "Raymond Still" <rstill@canada.com> To: <php-windows@lists.php.net> Sent: Wednesday, January 12, 2005 4:50 PM Subject: [PHP-WIN] help in understanding string / integer concatenation > Hello all; > I am a new PHP user. (But not new at programing.) I'm > running Win XP, Apache, PHP 5.0.3 (and PostgreSQL 8, > not that that should make a difference). > > I'm trying to use PHP to generate drop down lists of > arbitrary length in a form (<select> and <option>) > > I've come across something strange, to me, in using the > concatenation (.) operator. A simplified piece of code > follows. My question is, why is the output different > between the two versions? > apologies if I've missed something in the list archives. > Thanks in advance. > Ray > > <html> > <head> > <title>Untitled</title> > </head> > <body> > <?PHP > $i=4; > $str = 'hello "' . $i+1 . '"'; > echo $str; > > ?> > </body> > </html> > > > output: > -------------------- > > 1" > > > or, version 2, same as above except break > > $str = 'hello "' . $i+1 . '"'; > > into > > > $str = 'hello "'; > $str .= $i+1 . '"'; > > output becomes: > -------------------- > hello "5" (this is what I want to see) > > IE vs. netscape makes no difference. > > -- > PHP Windows Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >