Re: Re: ASP to PHP
| From: | Mark Rees | Date: | Fri, 09 Sep 2005 16:25:28 +0000 |
| Subject: | Re: Re: ASP to PHP | ||
| References: | 1 2 3 | Groups: | php.windows |
| Request: | Send a blank email to php-windows+get-26309@lists.php.net to get a copy of this message | ||
Please reply to the list.
I still don't understand the problem.
Anyway, you have this in your ASP file:
<input type="hidden" name="_VIEWSTATE" value="1"/>
When you submit that form to the PHP file, you can retrieve the value with
$_GET('_VIEWSTATE') or $_POST('_VIEWSTATE')
When you "go back" to the ASP page, what do you mean? Clicking "back" in the
browser, following a link, or submitting a form?
Clicking "back" in the browser?
?
following a link
put variable in the querystring and retrieve it
or submitting a form?
send the variable back as a form input
Yes, you were right on my logic. I fixed that but I went back to my original problem. Here is the
issue. In the asp code an input type hidden variable is set as name="_VIEWSTATE" and the
value is what in PHP is called as $_REQUEST["ESAuthCookie"]. Now the problem is that when
I go from the asp page to the php page this value is reset in php so when I go back to the asp page
and back to the php page I get an internal error because the _VIEWSTATE var is not the same in php
as it is in asp. So how can I go from asp page to the php page and maintain the same
variable's value?
Thanks for your help it is really appreciate it.
On 9/9/05, Mark Rees <mrees@itsagoodprice.com> wrote:
So I have I this problem. I have asp page that has a link to a PHP page,
when I click on the link I get the PHP with no problems but if I click back
to the asp page and click on the PHP page I get a HTTP 500 Internal server
error. If I hit the refresh button I get the php page again. The PHP page is
a form when the form is submitted after the fresh reload an error "the
directory name is invalid". Can anyone help me?
---------------------
I suspect there is a problem with the logic. It sounds like the PHP page is
not expecting to be called twice from the same link. More details are
required, perhaps including some code, for a better answer.
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