Re: php-windows Digest 11 Nov 2005 18:34:21 -0000 Issue 2820

What nextRecord() is? If it is the mysql_fetch_array then you're problem is that you call it in the while loop.. this is why the server crash! ( last line within while() remove it and try then!) If it is the mysql_fetch_row then you need to do this like while($i < mysql_num_rows(...)) { $nextRecord = $dbConn->nextRecord(); while ($nextRecord) { $book = new TBook($dbConn->field('NR_BOOK')); echo $book->getTitle().'<br>'; } $i++; } or something like this! the "(...)" = the result of the query.. i don't know exactly what functions you'r class have in it!

Hello to everyone, I'm manipulating objects in some scripts I've developed, and I've come across a doubt: I perform a query and do some checkings, but to perform this checkings I need to instantiate an object, and I really don't know how to do it without crashing theWeb Server. Let me give an example (I work in a Library and the example is directed to that): $dbConn->query('select nr_book from book_loan where cd_user = '.$cdUser); $nextRecord = $dbConn->nextRecord(); while ($nextRecord) { $book = new TBook($dbConn->field('NR_BOOK')); echo $book->getTitle().'<br>'; //how do I destroy the object here? $nextRecord = $dbConn->nextRecord(); } If I don't destroy the object the Web Server falls into some kind of deadlock and kills itself. And I didn't find a good explanation about how to do that in the PHP documentation in www.php.net I use Apache 2.0.54 as a Web Server and I use PHP 4.4.1 here at work.