Re: variable in an array? Answer: Double quotes

The answer to the interpolation problem is to use double quotes: $dsn = "{$servers["$id"]["type"]}://{$servers["$id"]["username"]}:{$servers["$id"]["password"]}@{$servers["$id"]["hostName"]}/{$servers["$id"]["databaseName"]}"; John Ellingsworth wrote:

Hi. I am sure there is an easy answer to this, but I do not know it and have not found the answer anywhere. I want to be able to dynamically set my database from an array of options: $database = array( array(

        "type" => "mssql",
        "name" => "database1",
        "hostName" => "hostname1",
        "username" => "username1",
        "password" => "password1",
        "databaseName" => "database1"),
    array(
        "type" => "mssql",
        "name" => "database2",
        "hostName" => "hostname2",
        "username" => "username2",
        "password" => "password2",
        "databaseName" => "database2"),

); // default database $id = 0; I am trying to use this line using PEAR DB, but the variable does not get interpreted so it never works (the line wraps; it is not the line wrapping): $dsn = "{$servers[$id]["type"]}://{$servers[$id]["username"]}:{$servers[$id]["password"]}@{$servers[$id]["hostName"]}/{$servers[$id]["databaseName"]}"; This works, so the problem is translating $id properly: $dsn = "{$servers[0]["type"]}://{$servers[0]["username"]}:{$servers[0]["password"]}@{$servers[0]["hostName"]}/{$servers[0]["databaseName"]}"; I would appreciate any help with this.

-- Thanks, John Ellingsworth Project Leader, Virtual Curriculum Academic Programs School of Medicine University of Pennsylvania (215) 573-4451 Virtual Curriculum http://www.cu2000.med.upenn.edu AIM: vc2000support To contact the Virtual Curriculum team: cu2000@mail.med.upenn.edu