Re: Help with Calendar Functions!!
| From: | Zak Greant | Date: | Fri, 10 Nov 2000 16:43:36 +0000 |
| Subject: | Re: Help with Calendar Functions!! | ||
| References: | 1 | Groups: | php.windows |
| Request: | Send a blank email to php-windows+get-3781@lists.php.net to get a copy of this message | ||
At 09:29 AM 11/10/00 -0700, Joey Garcia wrote:
I want to take a date such as 11/09/2000 and get the Julian day which would be something like 312, any suggestions would be much appreciated!!!! I tried to use the Julian2JD and JD2Julian but here are the results I got: $temp=juliantojd(11,09,2000); print $temp; I get a result of "0" with a day of "09", but I get "2451871" when I use just "9", I was hoping for the Julian day of the year. I divided 2451871 by 365.25 and subtracted 4713 and I got 1999, but why was this number returned?????09 - the leading 0 indicated that the number is octal base. Because 09 is an invalid octal number, 0 is substituted for it.
Also, I got weird results with the JD2Julian function $temp=jdtojulian(301); print $temp; I got the result of 10/28/-4713That's right JDs start in 4713 BC - BS is indicated with a leading -. --zak