Re: extracting value from array

Easiest (not best or fastest I'm sure) is Walk through the original array ... For(i=0,j=0; i < $array.count; i++) { //Look for your xyz123 (if its not there write to new array) if array(i) != "xyz123" { $array2(j) = $array(i) j++ } } //End For Loop //you'll now have a "new" array with all the values EXCEPT "xyz123" I know syntax is not correct .... but you should get the idea of the iteration afan@sprout.net wrote:

Hi all, my problem is following: let's say there is an array with 10 elements. $array = array('$value1', '$value2', '$value3', '$value4', '$value5', '$value6', '$value7', '$value8', '$value9', '$value10'); One of elements has value 'xyz123' - I do not know which one. How can I extract this element from the array and have a new array with all other element, except extracted one. Any idea? Afan Pasalic

-- Michael Kelley mkelley@nmsu.edu Programmer/Systems Analyst I New Mexico State University Information and Communication Technologies Work # (505)-646-1374 P.O. Box 30001 MSC: 3AT Las Cruces, NM 88003