Bug #17794 Updated: Setting a reference and value on one line

ID: 17794 Updated by: mfischer@php.net Reported By: greg@mtechsolutions.ca Status: Open -Bug Type: Scripting Engine problem +Bug Type: Documentation problem Operating System: should be independent PHP Version: 4.1.2 New Comment: You can't assign a value to a reference expression which is exactly what you try to do: &$b = 1; The same applies for the array operator. Moving it over to a documentation problem so the manual outlines this better. Previous Comments: ------------------------------------------------------------------------ [2002-06-16 23:51:16] greg@mtechsolutions.ca Since you can do: $a = $b = 1; It is only natural to assume you can also do: $a = &$b = 1; However, this returns a parse error. Should it not return a refernce to $b ? Although this (simple) example seems stupid, the reason this is a problem is when you involve arrays (and in my case, objects): $a = &$b[] = new Object(); I want to add a new object into $b, but I just want it to go to a new element number, without having to iterate through (which is currently the only work-around I can think of). At the same time, I need a reference to that object stored in another variable. I can't make a temporary object, as it will be lost (only the object in the $b array is stored permenantly) and it can't be a copy of the object, it has to be the specific instance stored in $b. If this has been fixed in ZE2, please disregard. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=17794&edit=1