Bug #51986 [Opn]: array_filter breaks references when a callback is used

From: Date: Thu, 03 Jun 2010 11:00:43 +0000
Subject: Bug #51986 [Opn]: array_filter breaks references when a callback is used
References: 1  Groups: php.bugs 
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Edit report at http://bugs.php.net/bug.php?id=51986&edit=1

 ID:               51986
 Updated by:       sjoerd@php.net
 Reported by:      daniel dot menard at ehesp dot fr
 Summary:          array_filter breaks references when a callback is used
 Status:           Open
 Type:             Bug
 Package:          Arrays related
 Operating System: Windows XP
 PHP Version:      5.3.2

 New Comment:

Use a reference in your callback function:

function my_trim(& $a)
{
	return trim($a);
}


Previous Comments:
------------------------------------------------------------------------
[2010-06-03 12:28:24] daniel dot menard at ehesp dot fr

Description:
------------
I have an array and a variable which is a reference on some element in
this array:
$arr=array('a'); $ref = &$arr[0]

If I apply array_filter() with a callback like trim() or count() on the
array, the reference is broken and $ref is no longer a reference (If I
apply array_filter() without a callback, the reference is not altered
and the result is correct).

I think that this is a regression introduced in php 5.2.11: with the
test script below, 5.2.10 give the good result, 5.2.11 do not.

I also tested with the latest version (5.3.2): same result, reference is
broken.

PS: I tested on windows XP with packages php-5.x.y-Win32-VC6-x86.zip
provided on this page:
http://windows.php.net/downloads/releases/archives/

Test script:
---------------
// Init
$arr = array('some value');
$ref = & $arr[0];

// Change $arr
$arr[0] = 'ONE';
echo 'step 1. $ref is ', ($ref !== 'ONE') ? 'BROKEN' : 'OK',
"\n";

// Apply array_filter (without callback) and change $arr
array_filter($arr);
$arr[0] = 'TWO';
echo 'step 2. $ref is ', ($ref !== 'TWO') ? 'BROKEN' : 'OK',
"\n";

// Apply array_filter (with a callback) then change $arr
array_filter($arr,'trim');
$arr[0] = 'THREE';
echo 'step 3. $ref is ', ($ref !== 'THREE') ? 'BROKEN' :
'OK', "\n";

Expected result:
----------------
step 1. $ref is OK
step 2. $ref is OK
step 3. $ref is OK

Actual result:
--------------
step 1. $ref is OK
step 2. $ref is OK
step 3. $ref is BROKEN


------------------------------------------------------------------------



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