Bug #51986 [Opn]: array_filter breaks references when a callback is used
Edit report at http://bugs.php.net/bug.php?id=51986&edit=1
ID: 51986
User updated by: daniel dot menard at ehesp dot fr
Reported by: daniel dot menard at ehesp dot fr
Summary: array_filter breaks references when a callback is used
Status: Open
Type: Bug
Package: Arrays related
Operating System: Windows XP
PHP Version: 5.3.2
New Comment:
Thanks for your comment: your workaround works.
However, having to redefine standard php functions like trim() or
count() just to be able to use them with array_filter() is not very
convenient, is it?
The fact is that the function behaviour changed in a "revision release"
which should not have broken my code...
;-)
Previous Comments:
------------------------------------------------------------------------
[2010-06-03 13:00:43] sjoerd@php.net
Use a reference in your callback function:
function my_trim(& $a)
{
return trim($a);
}
------------------------------------------------------------------------
[2010-06-03 12:28:24] daniel dot menard at ehesp dot fr
Description:
------------
I have an array and a variable which is a reference on some element in
this array:
$arr=array('a'); $ref = &$arr[0]
If I apply array_filter() with a callback like trim() or count() on the
array, the reference is broken and $ref is no longer a reference (If I
apply array_filter() without a callback, the reference is not altered
and the result is correct).
I think that this is a regression introduced in php 5.2.11: with the
test script below, 5.2.10 give the good result, 5.2.11 do not.
I also tested with the latest version (5.3.2): same result, reference is
broken.
PS: I tested on windows XP with packages php-5.x.y-Win32-VC6-x86.zip
provided on this page:
http://windows.php.net/downloads/releases/archives/
Test script:
---------------
// Init
$arr = array('some value');
$ref = & $arr[0];
// Change $arr
$arr[0] = 'ONE';
echo 'step 1. $ref is ', ($ref !== 'ONE') ? 'BROKEN' : 'OK',
"\n";
// Apply array_filter (without callback) and change $arr
array_filter($arr);
$arr[0] = 'TWO';
echo 'step 2. $ref is ', ($ref !== 'TWO') ? 'BROKEN' : 'OK',
"\n";
// Apply array_filter (with a callback) then change $arr
array_filter($arr,'trim');
$arr[0] = 'THREE';
echo 'step 3. $ref is ', ($ref !== 'THREE') ? 'BROKEN' :
'OK', "\n";
Expected result:
----------------
step 1. $ref is OK
step 2. $ref is OK
step 3. $ref is OK
Actual result:
--------------
step 1. $ref is OK
step 2. $ref is OK
step 3. $ref is BROKEN
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/bug.php?id=51986&edit=1
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