#19943 [Ver->Ctl]: Ragged array returns undefined results
| From: | sterling@php.net | Date: | Mon, 28 Oct 2002 02:08:18 +0000 |
| Subject: | #19943 [Ver->Ctl]: Ragged array returns undefined results | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-23512@lists.php.net to get a copy of this message | ||
ID: 19943
Updated by: sterling@php.net
Reported By: su-php@bossi.com
-Status: Verified
+Status: Critical
Bug Type: Arrays related
Operating System: Win2K
PHP Version: 4.3.0-dev
Previous Comments:
------------------------------------------------------------------------
[2002-10-16 22:51:14] iliaa@php.net
A pretty interesting bug this is, there appear to be 2 possible
behaviours that can happen here and only 1 is correct.
<?php
$ar = array();
for ( $count = 0; $count < 10; $count++ )
{
$ar[$count] = "$count";
$ar[$count]['idx'] = "$count";
}
for ( $count = 0; $count < 10; $count++ )
{
echo $ar[$count]." -- ".$ar[$count]['idx']."\n";
}
?>
The code above will output:
t 0 -- t
t 1 -- t
t 2 -- t
t 3 -- t
t 4 -- t
t 5 -- t
t 6 -- t
t 7 -- t
t 8 -- t
t 9 -- t
/home/rei/PHP_CVS/php4/Zend/zend_operators.c(1008) : Freeing
0x08369384 (6 bytes), script=a.php
Last leak repeated 9 times
If the " around the $count variable are removed then the script
reports:
Warning: Cannot use a scalar value as an array in
/home/rei/PHP_CVS/php4/a.php on line 7
/home/rei/PHP_CVS/php4/a.php(7) : Warning - Cannot use a scalar value
as an array
for every assignment and does no initialize any of the
$ar[$count]['idx'] values.
------------------------------------------------------------------------
[2002-10-16 19:54:16] su-php@bossi.com
However, the following codes does work, even though the array is still
ragged:
<?
$ragged = array();
for ( $count = 0; $count < 10; $count++ )
{
$ragged['idx'][$count] = 'ragged '.$count;
$ragged[$count] = 'single '.$count;
}
?>
<html><head></head><body>
<table border="1">
<tr>
<td>Expected</td><td>Actual</td>
<td>Expected IDX</td><td>Actual IDX</td>
</tr>
<?
for ( $count = 0; $count < 10; $count++ )
{
?>
<tr>
<td> <?= 'single '.$count ?> </td><td> <?= $ragged[$count]
?> </td>
<td> <?= 'ragged '.$count ?> </td><td> <?=
$ragged['idx'][$count] ?>
</td>
</tr>
<? } ?>
</table></body></html>
------------------------------------------------------------------------
[2002-10-16 19:50:57] su-php@bossi.com
When using an array that has ragged indices, the value in the array is
undefined. Well, actually it can be defined, but it is unexpected. No
errors or warnings are reported. Sample Code:
<?
$ragged = array();
for ( $count = 0; $count < 10; $count++ )
{
$ragged[$count] = 'single '.$count;
$ragged[$count]['idx'] = 'ragged '.$count;
}
?>
<html><head></head><body>
<table border="1">
<tr>
<td>Expected</td><td>Actual</td>
<td>Expected IDX</td><td>Actual IDX</td>
</tr>
<?
for ( $count = 0; $count < 10; $count++ )
{
?>
<tr>
<td> <?= 'single '.$count ?> </td><td> <?= $ragged[$count]
?> </td>
<td> <?= 'ragged '.$count ?> </td><td> <?=
$ragged[$count]['idx'] ?>
</td>
</tr>
<? } ?>
</table></body></html>
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=19943&edit=1