#19943 [Com]: Ragged array returns undefined results
ID: 19943
Comment by: Ppslim@ntlworld.com
Reported By: su-php@bossi.com
Status: Critical
Bug Type: Arrays related
Operating System: Win2K
PHP Version: 4.3.0-dev
New Comment:
I think this is pretty much invalid.
su-php@bossi.com posted 2 examples. Only 1 is correct, or infact, valid
code.
In the first example, you have the following 2 array assignments.
$ragged[$count] = 'single '.$count;
$ragged[$count]['idx'] = 'ragged '.$count;
In this, you assign a string to $ragged[$count], then, you turn it into
an array using $regged[$count]['idx'].
This is invlaid in most languages.
In the $ragged[$count], $ragged['idx'][$count] method, no type changes
are taking place.
Previous Comments:
------------------------------------------------------------------------
[2002-10-16 22:51:14] iliaa@php.net
A pretty interesting bug this is, there appear to be 2 possible
behaviours that can happen here and only 1 is correct.
<?php
$ar = array();
for ( $count = 0; $count < 10; $count++ )
{
$ar[$count] = "$count";
$ar[$count]['idx'] = "$count";
}
for ( $count = 0; $count < 10; $count++ )
{
echo $ar[$count]." -- ".$ar[$count]['idx']."\n";
}
?>
The code above will output:
t 0 -- t
t 1 -- t
t 2 -- t
t 3 -- t
t 4 -- t
t 5 -- t
t 6 -- t
t 7 -- t
t 8 -- t
t 9 -- t
/home/rei/PHP_CVS/php4/Zend/zend_operators.c(1008) : Freeing
0x08369384 (6 bytes), script=a.php
Last leak repeated 9 times
If the " around the $count variable are removed then the script
reports:
Warning: Cannot use a scalar value as an array in
/home/rei/PHP_CVS/php4/a.php on line 7
/home/rei/PHP_CVS/php4/a.php(7) : Warning - Cannot use a scalar value
as an array
for every assignment and does no initialize any of the
$ar[$count]['idx'] values.
------------------------------------------------------------------------
[2002-10-16 19:54:16] su-php@bossi.com
However, the following codes does work, even though the array is still
ragged:
<?
$ragged = array();
for ( $count = 0; $count < 10; $count++ )
{
$ragged['idx'][$count] = 'ragged '.$count;
$ragged[$count] = 'single '.$count;
}
?>
<html><head></head><body>
<table border="1">
<tr>
<td>Expected</td><td>Actual</td>
<td>Expected IDX</td><td>Actual IDX</td>
</tr>
<?
for ( $count = 0; $count < 10; $count++ )
{
?>
<tr>
<td> <?= 'single '.$count ?> </td><td> <?= $ragged[$count]
?> </td>
<td> <?= 'ragged '.$count ?> </td><td> <?=
$ragged['idx'][$count] ?>
</td>
</tr>
<? } ?>
</table></body></html>
------------------------------------------------------------------------
[2002-10-16 19:50:57] su-php@bossi.com
When using an array that has ragged indices, the value in the array is
undefined. Well, actually it can be defined, but it is unexpected. No
errors or warnings are reported. Sample Code:
<?
$ragged = array();
for ( $count = 0; $count < 10; $count++ )
{
$ragged[$count] = 'single '.$count;
$ragged[$count]['idx'] = 'ragged '.$count;
}
?>
<html><head></head><body>
<table border="1">
<tr>
<td>Expected</td><td>Actual</td>
<td>Expected IDX</td><td>Actual IDX</td>
</tr>
<?
for ( $count = 0; $count < 10; $count++ )
{
?>
<tr>
<td> <?= 'single '.$count ?> </td><td> <?= $ragged[$count]
?> </td>
<td> <?= 'ragged '.$count ?> </td><td> <?=
$ragged[$count]['idx'] ?>
</td>
</tr>
<? } ?>
</table></body></html>
------------------------------------------------------------------------
--
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Thread (8 messages)