Bug #16081: doesn't seem to honor fopen stdin position in code

From: mlnog@mlong.org Operating system: tru64 5.0a PHP version: 4.1.2 PHP Bug Type: Output Control Bug description: doesn't seem to honor fopen stdin position in code It appears that if I have a fopen to stdin anywhere in my code that PHP will prompt for stdin at the beginning of its execution instead of where I put it in the code. The following example shows it: #!/usr/local/bin/php <? print "BEFORE\n"; $cd=fopen("php://stdin","r"); $cd2=fread($cd,1); print "AFTER\n"; ?> Now as soon as I execute it, it sits and waits for me to enter stdin, then prints BEFORE AFTER It should be showing BEFORE and then prompt for STDIN, unless there is something major I am missing here. -- Edit bug report at http://bugs.php.net/?id=16081&edit=1 -- Fixed in CVS: http://bugs.php.net/fix.php?id=16081&r=fixedcvs Fixed in release: http://bugs.php.net/fix.php?id=16081&r=alreadyfixed Need backtrace: http://bugs.php.net/fix.php?id=16081&r=needtrace Try newer version: http://bugs.php.net/fix.php?id=16081&r=oldversion Not developer issue: http://bugs.php.net/fix.php?id=16081&r=support Expected behavior: http://bugs.php.net/fix.php?id=16081&r=notwrong Not enough info: http://bugs.php.net/fix.php?id=16081&r=notenoughinfo Submitted twice: http://bugs.php.net/fix.php?id=16081&r=submittedtwice