Bug #16081 Updated: doesn't seem to honor fopen stdin position in code
| From: | mfischer@php.net | Date: | Thu, 14 Mar 2002 19:56:22 +0000 |
| Subject: | Bug #16081 Updated: doesn't seem to honor fopen stdin position in code | ||
| References: | 1 | Groups: | php.bugs |
| Request: | Send a blank email to php-bugs+get-2518@lists.php.net to get a copy of this message | ||
ID: 16081
Updated by: mfischer@php.net
-Summary: doesn't seem to honor fopen stdin position in code
Reported By: mlnog@mlong.org
-Status: Open
+Status: Feedback
Bug Type: Output Control
Operating System: tru64 5.0a
PHP Version: 4.1.2
New Comment:
Maybe it's your terminal buffering?
Have you tried with 'flush();' after your print statements?
Previous Comments:
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[2002-03-14 14:51:20] mlnog@mlong.org
It appears that if I have a fopen to stdin anywhere in my code that PHP
will prompt for stdin at the beginning of its execution instead of
where I put it in the code.
The following example shows it:
#!/usr/local/bin/php
<?
print "BEFORE\n";
$cd=fopen("php://stdin","r");
$cd2=fread($cd,1);
print "AFTER\n";
?>
Now as soon as I execute it, it sits and waits for me to enter stdin,
then prints
BEFORE
AFTER
It should be showing BEFORE and then prompt for STDIN, unless there is
something major I am missing here.
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Edit this bug report at http://bugs.php.net/?id=16081&edit=1