#22177 [Opn->Bgs]: Warning: fopen() expects parameter 1 to be string

ID: 22177 Updated by: nicos@php.net Reported By: laudanp@yahoo.com -Status: Open +Status: Bogus Bug Type: Filesystem function related Operating System: RedHat PHP Version: 4.3.0 New Comment: As Jani said, tmpfile returns a resource, no need to try to fopen it. He said also that nothing was changed in 4.3.0 about it, which is right. Your code is bogus and I don't think it ever worked. See: http://www.php.net/manual/en/function.tmpfile.php resource tmpfile ( void) Creates a temporary file with an unique name in write mode, returning a file handle similar to the one returned by fopen(). The file is automatically removed when closed (using fclose()), or when the script ends. You should use: $temp = tmpfile(); fwrite($temp, "writing to tempfile"); fclose($temp); // this removes the file Not a bug->Bogus again. Previous Comments: ------------------------------------------------------------------------ [2003-02-11 15:52:09] laudanp@yahoo.com Per me previous comment addition, the code was not changed whatsoever. I'm "re-opening" this bug report in the hopes it will gather a response. ------------------------------------------------------------------------ [2003-02-11 15:50:52] laudanp@yahoo.com I don't appreciate the RTFM remark, but I am glad you replied back. I use the php manual extensively but have not seen that particular link. I can tell you honestly that your doubt is just that, because that same exact code block worked 100% under php 4.2.3. After the upgrade to 4.3 that code no longer works and it has *not* been changed. ------------------------------------------------------------------------ [2003-02-11 15:48:18] sniper@php.net RTFM: http://www.php.net/manual/en/function.tmpfile.php tmpfile() returns a file handle already..NOT filename. I doubt this ever worked for you as this was not changed in 4.3.0...(you propably used tempnam() instead before) ------------------------------------------------------------------------ [2003-02-11 15:39:40] laudanp@yahoo.com A php script I have worked fine under PHP 4.2.3, but after the upgrade to PHP 4.3 whenever I try running it I get these errors: Warning: fopen() expects parameter 1 to be string, resource in ... on line 353 Warning: fwrite(): supplied argument is not a valid stream resource in ... on line 354 Warning: fclose(): supplied argument is not a valid stream resource in ... on line 355 Warning: getimagesize(Resource id #4) [function.getimagesize]: failed to create stream: No such file or directory in ... on line 361 The following blocks of code surround the problematic lines from above: if ($input = fopen($image, "rb")) { $image_data = fread ($input, 2048576); fclose($input); if (!$tmp_image = @tmpfile()) { exit("Cannot create tempfile using tmpfile()."); } 353: $output = fopen($tmp_image, "wb"); 354: fwrite($output, $image_data); 355: fclose($output); 356: } else { 357: exit("Cannot access ".$image." for reading. (Does not exist or has wrong permissions)"); 358: } 359: 360: // Create Image from file by type, get and set size 361: list($width,$height,$type) = getimagesize($tmp_image); 362: I'm having difficulty determining what the problem is since the code worked with PHP 4.2.3. Thanks for your help. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=22177&edit=1