#22177 [Bgs->Csd]: Warning: fopen() expects parameter 1 to be string

ID: 22177 User updated by: laudanp@yahoo.com Reported By: laudanp@yahoo.com -Status: Bogus +Status: Closed Bug Type: Filesystem function related Operating System: RedHat PHP Version: 4.3.0 New Comment: I don't consider this bogus and your thoughts are your own. I wouldn't be the type to just submit a bug report that I didn't think was founded. The code worked under 4.2.3 and if you care to check I can send the whole package to you to disprove your "thoughts". Upgrading to php 4.3 has broken the subroutine. Instead of "thinking" that it doesn't work I would suspect more from php developers for a more quantitative analysis of the situation. Ergo I prefer to close this bug report myself because I'm apparently not getting any constructive feedback here, instead of having it labeled as "bogus". Once again, the code, unchanged prior 4.3 worked. The same exact code that worked no longer does. Absolutely nothing has been changed. Anyhow, thanks for replying at least. It is much better to know where one stands rather than not getting any reply whatsoever. Previous Comments: ------------------------------------------------------------------------ [2003-02-11 15:59:23] nicos@php.net As Jani said, tmpfile returns a resource, no need to try to fopen it. He said also that nothing was changed in 4.3.0 about it, which is right. Your code is bogus and I don't think it ever worked. See: http://www.php.net/manual/en/function.tmpfile.php resource tmpfile ( void) Creates a temporary file with an unique name in write mode, returning a file handle similar to the one returned by fopen(). The file is automatically removed when closed (using fclose()), or when the script ends. You should use: $temp = tmpfile(); fwrite($temp, "writing to tempfile"); fclose($temp); // this removes the file Not a bug->Bogus again. ------------------------------------------------------------------------ [2003-02-11 15:52:09] laudanp@yahoo.com Per me previous comment addition, the code was not changed whatsoever. I'm "re-opening" this bug report in the hopes it will gather a response. ------------------------------------------------------------------------ [2003-02-11 15:50:52] laudanp@yahoo.com I don't appreciate the RTFM remark, but I am glad you replied back. I use the php manual extensively but have not seen that particular link. I can tell you honestly that your doubt is just that, because that same exact code block worked 100% under php 4.2.3. After the upgrade to 4.3 that code no longer works and it has *not* been changed. ------------------------------------------------------------------------ [2003-02-11 15:48:18] sniper@php.net RTFM: http://www.php.net/manual/en/function.tmpfile.php tmpfile() returns a file handle already..NOT filename. I doubt this ever worked for you as this was not changed in 4.3.0...(you propably used tempnam() instead before) ------------------------------------------------------------------------ [2003-02-11 15:39:40] laudanp@yahoo.com A php script I have worked fine under PHP 4.2.3, but after the upgrade to PHP 4.3 whenever I try running it I get these errors: Warning: fopen() expects parameter 1 to be string, resource in ... on line 353 Warning: fwrite(): supplied argument is not a valid stream resource in ... on line 354 Warning: fclose(): supplied argument is not a valid stream resource in ... on line 355 Warning: getimagesize(Resource id #4) [function.getimagesize]: failed to create stream: No such file or directory in ... on line 361 The following blocks of code surround the problematic lines from above: if ($input = fopen($image, "rb")) { $image_data = fread ($input, 2048576); fclose($input); if (!$tmp_image = @tmpfile()) { exit("Cannot create tempfile using tmpfile()."); } 353: $output = fopen($tmp_image, "wb"); 354: fwrite($output, $image_data); 355: fclose($output); 356: } else { 357: exit("Cannot access ".$image." for reading. (Does not exist or has wrong permissions)"); 358: } 359: 360: // Create Image from file by type, get and set size 361: list($width,$height,$type) = getimagesize($tmp_image); 362: I'm having difficulty determining what the problem is since the code worked with PHP 4.2.3. Thanks for your help. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=22177&edit=1