#35765 [Fbk->Opn]: fopen wrapper using invalid SIZE command

ID: 35765 User updated by: jasonandtonya at gmail dot com Reported By: jasonandtonya at gmail dot com -Status: Feedback +Status: Open Bug Type: FTP related Operating System: * PHP Version: 5.1.1 New Comment: Same error. Apache/2.0.49 (Win32) PHP/5.1.2-dev Server Previous Comments: ------------------------------------------------------------------------ [2005-12-21 18:47:39] sniper@php.net Please try using this CVS snapshot: http://snaps.php.net/php5.1-latest.tar.gz For Windows: http://snaps.php.net/win32/php5.1-win32-latest.zip ------------------------------------------------------------------------ [2005-12-21 18:28:40] jasonandtonya at gmail dot com Description: ------------ when opening a file via ftp as an array $logfile=fopen('ftp://example.com/filename.ext',"r"); it returns an error: 500 'SIZE filename.ext': command not understood and example.com is running a Solaris default ftp daemon. Looking at the latest version 5.1-latest, (I'm assuming that it is using ftp_fopen_wrapper.c): ftp_fopen_wrapper.c,v 1.85.2.2 2005/11/22 03:01:39 line 450: /* find out the size of the file (verifying it exists) */ php_stream_printf(stream TSRMLS_CC, "SIZE %s\r\n", resource->path); Is there a reason that you are using a non-standard command SIZE for verifying existance of the file? Reproduce code: --------------- $file=fopen('ftp://example.com/filename.ext',"r"); Expected result: ---------------- No error message when doing fopen Actual result: -------------- Warning: fopen('ftp://example.com/filename.ext') [function.fopen]: failed to open stream: FTP server reports 500 'SIZE filename.ext': command not understood. in /patrh/to/htdocs/filename.php on line 3 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=35765&edit=1