Re: output problem

From: Date: Thu, 23 May 2002 14:02:57 +0000
Subject: Re: output problem
References: 1  Groups: php.db 
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If I am not mistaken, try printing $line["user"] instead of just $line as in: <?php #error_reporting(E_ALL); echo date("Y-m-d"); print $date; mysql_connect("servername", "user", "password") or die("Connect failed"); $query = "select count(user) from log_request where date='$date' and status = 'open'"; $result = mysql_db_query("call_manage", "$query") or die("query failed"); while($line = mysql_fetch_object($result)) { print ("<table width=100% border=0><td><tr bgcolor=#f0f0f0>"); print ("<br><b> </b>$line["user"]->user<br>\n"); print ("</td></tr>"); } ?> Cami ----- Original Message ----- From: "Chris Grigor" <cgrigor@mweb.com> To: <php-db@lists.php.net> Sent: Thursday, May 23, 2002 2:46 PM Subject: [PHP-DB] output problem Howdi Alll some of you might laugh at this but I cant get this to work.... Im doing a count on a field and want to diplay the result here is an example... <?php #error_reporting(E_ALL); echo date("Y-m-d"); print $date; mysql_connect("servername", "user", "password") or die("Connect failed"); $query = "select count(user) from log_request where date='$date' and status = 'open'"; $result = mysql_db_query("call_manage", "$query") or die("query failed"); while($line = mysql_fetch_object($result)) { print ("<table width=100% border=0><td><tr bgcolor=#f0f0f0>"); print ("<br><b> </b>$line->user<br>\n"); print ("</td></tr>"); } ?> what am I missing as it returns no value at all from $line->user, should I be doing this differently?? Thankyou Chris -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php

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