Re: output problem
| From: | Stephen Rhodes | Date: | Thu, 23 May 2002 18:49:25 +0000 |
| Subject: | Re: output problem | ||
| References: | 1 | Groups: | php.db |
| Request: | Send a blank email to php-db+get-19406@lists.php.net to get a copy of this message | ||
When you write the SQL statement write it as:
select count(user) AS count from log_request where date='$date' and
status = 'open'
(note i have added 'AS count' in there so it stores the value in
'count')
Now when you output the result write it as $line->count
Cheers
Steve
"Chris Grigor" <cgrigor@mweb.com> wrote in message
news:6F76E514B4D4EA469DACC8D4E2F2AF9B45DEF1@mwjdc2.mweb.com...
Howdi Alll
some of you might laugh at this but I cant get this to work....
Im doing a count on a field and want to diplay the result here is an
example...
<?php
#error_reporting(E_ALL);
echo date("Y-m-d");
print $date;
mysql_connect("servername", "user", "password")
or die("Connect failed");
$query = "select count(user) from log_request where date='$date' and
status = 'open'";
$result = mysql_db_query("call_manage", "$query")
or die("query failed");
while($line = mysql_fetch_object($result))
{
print ("<table width=100% border=0><td><tr bgcolor=#f0f0f0>");
print ("<br><b> </b>$line->user<br>\n");
print ("</td></tr>");
}
?>
what am I missing as it returns no value at all from $line->user, should I
be
doing this differently??
Thankyou
Chris