Re: mysql/php query problem really bugging me
| From: | chip dot wiegand at simrad dot com | Date: | Tue, 06 Aug 2002 22:49:57 +0000 |
| Subject: | Re: mysql/php query problem really bugging me | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-21026@lists.php.net to get a copy of this message | ||
Jason Wong <phplist@gremlins.com.hk> wrote on 08/06/2002 01:59:39 PM:
> On Wednesday 07 August 2002 04:51, chip.wiegand@simrad.com wrote:
> > I have a database and several tables on a mysql server maintained by my
> > ISP. I have set up another
> > mysql/php/apache server in my office. I have copied the
database/tables/web
> > pages from the ISP's
> > server onto my server. Everything works great on my own server except
the
> > queries to one particular
> > table. Here is the error I am getting:
> >
> > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result
> > resource in
> > /usr/local/apache/htdocs/bulletin_out.php on line 22
> >
> > This same page works fine on the ISP's server, but my copy is not
working
> > on my server.
> Have you performed the obvious debugging procedures (like printing out
the key
> variables to ensure that they contain what you expect)?
> --
> Jason Wong -> Gremlins Associates -> www.gremlins.com.hk
I'm not sure how to do that on a page with no <form>, just html <a href>
links.
The url does appear to be correct -
http://157.237.65.118/bulletin_sorter.php?orderby=vlad
The above should select only the bulletins authored by Vlad, and it does
work on
the ISP's server, but not on my server.
I noticed the ISP is running MySQL-3.23.26 and I'm running 3.23.51, if that
makes
any differance.
--
Chip