RE: [PHP-DB] % operator

Although now that I look at: http://us4.php.net/manual/en/language.operators.arithmetic.php You'll see that $a % $b resturns the modulus so that is probably the easiest. Andrew, At 11:43 AM 8/12/2003, you wrote:

There's probably a better way to do this, but to retrieve only the 0.8 from 24/5 try this: ($a/$b)-floor($a/$b) Regards, Matt. -----Original Message----- From: Alain Barthélemy [mailto:cassandre@bartydeux.be] Sent: Tuesday, August 12, 2003 5:05 AM To: php-db Subject: [PHP-DB] % operator Hello, If you have $a = 24; $b = 5; and $c = $a/$b; ===> $c = 4.8 To retrieve the .8 (reste in french) I saw instruction: $a%$b Where can I find a manual for this '%' operator? Of course I already looked in all the Php manuals (operators, etc ...). Thanks, -- Alain Barthélemy cassandre@bartydeux.be http://bartydeux.be Linux User #315631 -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php