RE: [PHP-DB] % operator

Well, it looks like your previous response was correct, but $a%$b in this case returns 4, not the 0.8 as intended ... fmod($a, $b) (I have php 4.1.2, so I can't test fmod()) will probably return 0.8 though. As a side note, this message seems a little off-topic ... though it is PHP, it has nothing to do with databases. :) Regards, Matt. -----Original Message----- From: Andrew D. Luebke [mailto:andrew@copeandmcphetres.com] Sent: Tuesday, August 12, 2003 3:04 PM To: 'Alain Barthélemy'; php-db Subject: RE: [PHP-DB] % operator Although now that I look at: http://us4.php.net/manual/en/language.operators.arithmetic.php You'll see that $a % $b resturns the modulus so that is probably the easiest. Andrew, At 11:43 AM 8/12/2003, you wrote: >There's probably a better way to do this, but to retrieve only the 0.8 from >24/5 try this: > >($a/$b)-floor($a/$b) > >Regards, >Matt. > >-----Original Message----- >From: Alain Barthélemy [mailto:cassandre@bartydeux.be] >Sent: Tuesday, August 12, 2003 5:05 AM >To: php-db >Subject: [PHP-DB] % operator > > >Hello, > >If you have > >$a = 24; >$b = 5; > >and > >$c = $a/$b; > >===> $c = 4.8 > >To retrieve the .8 (reste in french) I saw instruction: > >$a%$b > >Where can I find a manual for this '%' operator? Of course I already looked >in >all the Php manuals (operators, etc ...). > >Thanks, > > > >-- >Alain Barthélemy >cassandre@bartydeux.be >http://bartydeux.be >Linux User #315631 > > >-- >PHP Database Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php > >-- >PHP Database Mailing List (http://www.php.net/) >To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php