Re: Php if statement in a form

From: Date: Fri, 06 Aug 2004 02:57:35 +0000
Subject: Re: Php if statement in a form
References: 1  Groups: php.db 
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try this?? if($row['timeout']=="") { echo "<input name='timeout' type='text' value='".date('H:i')."'>"; }else{ print $row["timeout"]; } ----- Original Message ----- From: <Justin.Baiocchi@csiro.au> To: <php-db@lists.php.net> Sent: Friday, August 06, 2004 10:50 AM Subject: RE: [PHP-DB] Php if statement in a form > Well, this works: so you were all on the right track > > if($row['timeout']=="") > { > print "<input name='timeout' type='text' value='"echo > date('H:i')"'>"; > }else{ > print $row["timeout"]; > } > > But now I get a parse error on the <input> line > > > -----Original Message----- > From: Ng Hwee Hwee [mailto:hhwee@towa.com.sg] > Sent: Friday, 6 August 2004 12:30 PM > To: php-db@lists.php.net > Subject: Re: [PHP-DB] Php if statement in a form > > > what about this? > > if(empty($row["timeout"])) > > > ----- Original Message ----- > From: "Doug Thompson" <dthompson@brickbarn.com> > To: <Justin.Baiocchi@csiro.au> > Cc: <php-db@lists.php.net> > Sent: Friday, August 06, 2004 10:18 AM > Subject: Re: [PHP-DB] Php if statement in a form > > > > if (is_null($row["timeout"]).....) > > > > Justin.Baiocchi@csiro.au wrote: > > > Still no joy. The parse error actually refers to the -- if > > > ($row["timeout"] IS NULL); --- line. > > > > > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php >

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