RE: [PHP-DB] Php if statement in a form (solved)
| From: | Justin dot Baiocchi at csiro dot au | Date: | Fri, 06 Aug 2004 02:56:06 +0000 |
| Subject: | RE: [PHP-DB] Php if statement in a form (solved) | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-35615@lists.php.net to get a copy of this message | ||
Not to worry - manage to solve the problem using the line below
$date=date('H:i');
echo "<input name=\"timeout\" type=\"text\"
value=\"$date\">";
Thanks for all the input
-----Original Message-----
From: Baiocchi, Justin (CSIRO IT, Armidale)
Sent: Friday, 6 August 2004 12:50 PM
To: php-db@lists.php.net
Subject: RE: [PHP-DB] Php if statement in a form
Well, this works: so you were all on the right track
if($row['timeout']=="")
{
print "<input name='timeout' type='text' value='"echo
date('H:i')"'>";
}else{
print $row["timeout"];
}
But now I get a parse error on the <input> line
-----Original Message-----
From: Ng Hwee Hwee [mailto:hhwee@towa.com.sg]
Sent: Friday, 6 August 2004 12:30 PM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Php if statement in a form
what about this?
if(empty($row["timeout"]))
----- Original Message -----
From: "Doug Thompson" <dthompson@brickbarn.com>
To: <Justin.Baiocchi@csiro.au>
Cc: <php-db@lists.php.net>
Sent: Friday, August 06, 2004 10:18 AM
Subject: Re: [PHP-DB] Php if statement in a form
> if (is_null($row["timeout"]).....)
>
> Justin.Baiocchi@csiro.au wrote:
> > Still no joy. The parse error actually refers to the -- if
> > ($row["timeout"] IS NULL); --- line.
> >
> >
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